16x^2+80x+100=160

Solution for 16x^2+80x+100=160 equation:

16x^2+80x+100=160

We move all terms to the left:

16x^2+80x+100-(160)=0

We add all the numbers together, and all the variables

16x^2+80x-60=0

a = 16; b = 80; c = -60;
Δ = b2-4ac
Δ = 802-4·16·(-60)
Δ = 10240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10240}=\sqrt{1024*10}=\sqrt{1024}*\sqrt{10}=32\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-32\sqrt{10}}{2*16}=\frac{-80-32\sqrt{10}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+32\sqrt{10}}{2*16}=\frac{-80+32\sqrt{10}}{32}
$